Y= x(1 x) (1=2;1=4) The region Dis both vertically simple and horizontally simple, but the bounds for yin terms of x are simpler than the bounds for xin terms of y, so when we use Fubini's theorem to evaluate the integral, we take the yintegral on the inside and the xintegral on the outside This gives us ZZ D f(x;y)dA= Z x=1=2 x=0 Z y=x(1(b)What is the PDF of X?5 Z 1 5 5 1 3x 4xydydx = Z dx 0 2xy2 = 55 0 Z 0 2 dx = 3 16 34 Joint cumulative distribution function Suppose X and Y are jointlydistributed random variables We will use the notation 'X x;
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(x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2z intersect
(x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2z intersect-Algebra Solve for x (xy)/3=5 x y 3 = 5 x y 3 = 5 Multiply both sides of the equation by 3 3 3⋅ xy 3 = 3⋅5 3 ⋅ x y 3 = 3 ⋅ 5 Simplify both sides of the equation Tap for more steps Cancel the common factor of 3 3 Tap for more steps3x2y=12,xy=5 To solve a pair of equations using substitution, first solve one of the equations for one of the variables Then substitute the result for that variable in the other equation 3x2y=12 Choose one of the equations and solve it for x by isolating x
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More You need to find the x values on both lines and multiply them together to find the value for the new graph of f*g (x) For example at x=4, g (4)=0 and f (4)=4 so f*g (4)=0 (multiply the two values together) When x=6, g (6)=1 and f (6)=6 so f*g (6)=6Lista 5com respostas PROFESSOR KOSTIATYN IUSENKO MAT0134 2 semestre de 16 1 Espac¸os com produto interno Exerc´ıcio1 Consideremos o espac¸o euclidiano R 2Sendo u= (1;2) e v= ( 1;1) em R determine um vetor wdesseShow that the two lines x 1/2 = y2/3 = z3/4 and x 4/5 = y 1/2 = z intersect Find also the point of intersection of these lines asked in Mathematics by Niharika ( 756k points)
Consider the level surface given by x2 y2 z2 = 2 Match the slices with their correct plots below Slice for y = 0 Slice for x = 2 Slice for y = 2 Slice for x = 1 Note In order to get credit for this problem all answers must be correct Verify associativity of addition of rational numbers ie, (xy)z = x(yz), when (i) x = \(\frac{1}{2}\) \(\frac{3}{5}\),z = \(\frac{4}{3}\)Tìm x y z(x1)2=(y2)3=(z1)5 và xyz=14
Substitute t= 4u2 1;u2 = 1 4 (t 1);STA 247 — Answers for practice problem set #1 Question 1 The random variable X has a range of {0,1,2} and the random variable Y has a range of {1,2}Click here👆to get an answer to your question ️ Find the shortest distance between the lines x 1/2 = y 2/3 = z 3/4 and x 2/3 = y 4/4 = z 5/5
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Show that the lines x 1/2 = y 2/3 = z 3/4 and x 4/5 = y 1/2 = z intersect Also, find their point of intersection asked in 3D Coordinate Geometry by Anika01 (II Let x1, x2, , x n be a random sample drawn from a population with mean µ and variance σ2In other words, E(xi) = µ, and Var (xi) = σ 2 for i = 1, 2, , n, and the x's are all independent of each otherLet ∑ n i xi n x 1 1 be the sample mean (a) (4 points) Show that E(x) = µE( x ) = E (∑n i xi n 1 1) = n 1 E(∑) = n i xi 1 n 1 ∑ n i E xiVerify Associativity of Addition of Rational Numbers IE, (X Y) Z = X (Y Z), When X = 1 2 , Y = 2 3 , Z = − 1 5 \\text{We have to verify that} (x y
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Substituting for the impulse response gives y(t) = Z 1 1 x(˝)h ˝(t)d˝ This is a superposition integral The values of x(˝)h(t;˝)d˝are superimposed (added up) for each input time ˝How do you find the equation of the line passing through the point math(1,2,3)/math and perpendicular to the lines math\frac{x}{1}=\frac{y}{2}=\frac{z}{3Problem 456 Solution From Appendix A, an Erlang random variable Xwith parameters >0 and nhas PDF f X(x) = ˆ nxn 1e x=(n
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X2 − 4y 2 12y z − 9z 2 View solution steps Solution Steps (x2y3z) (x2y3z) ( x 2 y − 3 z) ( x − 2 y 3 z) Apply the distributive property by multiplying each term of x2y3z by each term of x2y3z Apply the distributive property by multiplying each term ofX^2y^2z^2=1 WolframAlpha Rocket science? Verify associativity x=1/2 y=2/3 z=1/5 of multiplication of rational number maruthi46 is waiting for your help Add your answer and earn points
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Not a problem Unlock StepbyStep1 8 dt= udu changing the bounds, we get = 1 2 Z 5 1 1 4 (t 1) p t 1 8 dt = 1 64 Z 5 1 t3=2 t1=2 dt 1 64 2 5 t5=2 2 3 t3=2 5 1 = 5 48 p 5 1 240 11 Evaluate RR S x 2z2 dS, where Sis the part of the cone z2 = x2 y between the planes z= 1 and z= 3 The widest point of Sis at the intersection of the cone and the plane z= 3, where x2 y2 = 32 = 9;(x 1)/3 = (y 1)/2 = (z 1)/5 and (x 2)/4 = (y 1)/3 = lines are ____ (A) parallel (B) coincident Intersecting (D) skew
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Academiaedu is a platform for academics to share research papers) random variable with parameter = 1=3 and expected value EX = 15 (a)What is the value of the parameter n?Eqnof the first line is (x1)/3 = (y1)/2 = (z1)/5 = m for some real m Any point on this line is of the form (3m1, 2m1, 5m1) Eqnof the second line is (x2)/4 = (y1)/3 = (z1)/2 = n for some real n Any point on this line is of the form (4
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Z 1 5 f Y (y) dy= e y=5 1 5 = e 1 (3) Problem 456 Xis an Erlang (n; In particular, for x = 125 we have P(125, ) and m = x 1 = 225 Hence the equation of the tangent line, in point slope form is y − 1 = Transcript Misc (Method 1) Find the vector equation of the line passing through the point (1, 2, –4) and perpendicular to the two lines (𝑥 − 8)/3 = (𝑦 19)/(−16) = (𝑧 − 10)/7 and (𝑥 − 15)/3 = (𝑦 − 29)/8 = (𝑧 − 5)/(−5) The vector equation of a line passing through a point with position vector 𝑎 ⃗ and parallel to a vector 𝑏 ⃗ is 𝒓 ⃗ = 𝒂
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